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X^2+5X+4=0.5X+1
We move all terms to the left:
X^2+5X+4-(0.5X+1)=0
We get rid of parentheses
X^2+5X-0.5X-1+4=0
We add all the numbers together, and all the variables
X^2+4.5X+3=0
a = 1; b = 4.5; c = +3;
Δ = b2-4ac
Δ = 4.52-4·1·3
Δ = 8.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{8.25}}{2*1}=\frac{-4.5-\sqrt{8.25}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{8.25}}{2*1}=\frac{-4.5+\sqrt{8.25}}{2} $
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